• Matéria: Matemática
  • Autor: tueman23
  • Perguntado 4 anos atrás

gente me ajuda pelo amor de Deus!​

Anexos:

Respostas

respondido por: diegosouzads2011
1

Explicação passo-a-passo:

Valor de x

\sf x=\Big(2-\dfrac{1}{2}\Big)^{-2}

\sf x=\Big(\dfrac{4}{2}-\dfrac{1}{2}\Big)^{-2}

\sf x=\Big(\dfrac{3}{2}\Big)^{-2}

\sf x=\Big(\dfrac{2}{3}\Big)^2

\sf x=\dfrac{2^2}{3^2}

\sf x=\dfrac{4}{9}

Valor de y

\sf y=\Big(1+\dfrac{1}{3}\Big)^{-1}

\sf y=\Big(\dfrac{3}{3}+\dfrac{1}{3}\Big)^{-1}

\sf y=\Big(\dfrac{4}{3}\Big)^{-1}

\sf y=\dfrac{3}{4}

Assim:

\sf x\cdot y=\dfrac{4}{9}\cdot\dfrac{3}{4}

\sf x\cdot y=\dfrac{12}{36}

\sf x\cdot y=\dfrac{12\div12}{36\div12}

\boxed{\red{\sf x\cdot y=\dfrac{1}{3}}}

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