Question

Determine as coordenadas do ponto M(a,b), ponto médio do segmento AB, sendo dados A(1,-1) e B(3, 5).

Answer 1

Xm = $\frac{xA+xB}{2}$

Ym = $\frac{yA+yB}{2}$

Xm = $\frac{1+3}{2}$

Xm = $\frac{4}{2}$

Xm = 2

Ym = $\frac{-1+5}{2}$

Ym = $\frac{4}{2}$

Ym = 2

M = (2,2)

Answer 2

O ponto médio de um segmento é determinado por:
$X_m= \frac{x_1+x_2}{2} ~~~~~~~~~~ e ~~~~~~~~~~ Y_m= \frac{y_1+y_2}{2}$

Calculando o ponto médio do segmento A(1,-1) e B(3,5):
$X_m= \frac{x_1+x_2}{2} ~~~~~~~~~~ e ~~~~~~~~~~ Y_m= \frac{y_1+y_2}{2} \\ \\ X_m= \frac{1+3}{2} ~~~~~~~~~~~~ e ~~~~~~~~~~~ Y_m= \frac{-1+5}{2} \\ \\ X_m= \frac{4}{2} ~~~~~~~~~~~~~~~ e ~~~~~~~~~~~ Y_m= \frac{4}{2} \\ \\ \boxed{X_m= 2 ~~~~~~~~~~~~~~ e ~~~~~~~~~~~~ Y_m= 2}$