Question

URGENTEEEEE Caucule as potências: a)(0,7)^0 b)(1,2)^-1 c)(0,31)^-2 d)(1/3)^2 e)(-5)^2 f)(-1)^4

Answer 1

$a)0,7^0~=1\\\\ b)1,2^{-1}~= \frac{1}{1,2}~=~0,83\\\\ c)0,31^{-2}~=~ \frac{1}{0,32^2} ~=9,76\\\\ d) \frac{1^2}{3^2}= \frac{1}{9}\\\\ e)(-5)^2= 25 \\\\ f)(-1)^4=1 \\ \\ \\ att:~Jhonny$

Answer 2

$a)~~(0,7)^0\to~~\boxed{\boxed{~1~}}\\\\\\\\ b)~~ (1,2)^{-1}\to~~ \left( \dfrac{1}{1,2} \right) ^1\to~~ \dfrac{1}{1,2} \to~~ \dfrac{1}{ \dfrac{12}{10} } \to~~ 1\times \dfrac{10}{12}\to~~ \boxed{\boxed{~\dfrac{10}{12}~}} \\\\\\\\ c)~~(0,31)^{-2}\to~~ \left( \dfrac{1}{0,31} \right) ^2\to~~ \left( \dfrac{1}{0,31} \right) .\left( \dfrac{1}{0,31} \right)\to~~ \dfrac{1}{0,0961 }\to\\\\ \dfrac{1}{ \dfrac{961}{10000} } \to~~ 1\times \dfrac{10000}{961} \to~~ \boxed{\boxed{~\dfrac{10000}{961}~}}$




$d)~~ \left( \dfrac{1}{3} \right) ^2\to~~ \dfrac{1^2}{3^2} \to~~ \boxed{\boxed{~ \dfrac{1}{9} ~}}\\\\\\\\ e)~~(-5)^2\to~~(-5)(-5)\to~~\boxed{\boxed{~25~}}\\\\\\\\ f)~~ (-1)^4\to~~(-1)(-1)(-1)(-1)\to~~ \boxed{\boxed{~1~}}$