Question

log base 2 2elevado a x²- 3x + 5=3

Answer 1

Log [2] 2^x²-3x+5=3
Pelas propriedades dos logaritmos:
(x²-3x+5).Log [2] 2
(x²-3x+5).1=3
x²-3x+5=3
x²-3x+5-3=0
x²-3x+2=0
delta=b²-4ac
delta=1
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x=-(-3)+-V1/2
x=3+1/2
x=4/2
x=2
x=3-1/2
x=2/2
x=1
Testando:
Log [2] 2^1²-3.1+5=3
Log[2] 2^1-3+5=3
Log[2]2^3=3
Log[2]8=3(correto)
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Log [2]2^(2²-3.2+5)=3
Log [2]2^(4-6+5)=3
Log[2]2^(-2+5]
Log[2]2^3
Log[2] 8 = 3,pois 2³=8
Resposta x=2 e x=1