Question

Determine o valor do pH de soluções com:
a) [OH^-]=10^-3 mol/L
b) [OH^-]=10^-10 mol/L

Answer 1

$OH^- = -Log(10^-^3)$

$OH^- = -(-3)*Log(10)$

$OH^- = 3*(1)$

$OH^- = 3$

$OH^- + PH^+ = 14$

$3 + PH^+ = 14$

$PH = 14 -3$

$PH = 11$


B)

$OH^- = -Log(10^-^1^0)$

$OH^- = -(-10)*Log(10)$

$OH^- = 10*1$

$OH^- = 10$

$PH + OH = 14$

$PH + 10 = 14$

$PH = 14 -10$

$PH = 4$