Question

calcule o perímetro do triângulo de vértices A(1,3) B (1,-2 ) E C (5,0)

Answer 1

Ola Mica

AB = 0² + 5² = 25
AB = 5 

BC² = 4² + 2² = 16 + 4 = 20
BC = 2√5 

AC² = 4² + 3² = 16 + 9 = 25
AC = 5

perímetro

P = 5 + 2√5 + 5 = 10 + 2√5 = 14.1421

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Answer 2

Dab=$\sqrt{(1-1)^{2} } + (3+2)^{2}$
Dab=$\sqrt{ 5^{2} }$
Dab=$\sqrt{25}$
Dab=5

Dbc= $\sqrt{(1-5)^{2}+(-2-0$
Dbc=$\sqrt{(-4)^{2}+ (-2)^{2} }$
Dbc=$\sqrt{16+4}$
Dbc=$\sqrt{20}$
Dbc=2$\sqrt{5}$

Dac=$\sqrt{(1-5)^{2} + (3-0)^{2} }$
Dac=$\sqrt{(-4)^{2} + 3^{2} }$
Dac=$\sqrt{16+9}$
Dac=$\sqrt{25}$
Dac=5

Perímetro= 5+ 5 +2$\sqrt{5}$
Perímetro=10+2$\sqrt{5}$