Question

e)$\sqrt{112}+ \sqrt{14}- \sqrt{28}$

g)$\sqrt{8}+ \sqrt{32}+ \sqrt{72}- \sqrt{50}=$

Cada pessoa responde uma pergunta se quiserem, vale 6 pontos pra cada.

Answer 1

$\sqrt{112} + \sqrt{14}- \sqrt{28} } . \sqrt{2^{2}. 2^{2}} . \sqrt{2} + \sqrt{14} - \sqrt{2^{2}} . \sqrt{7} . 4 \sqrt{7} + 2 \sqrt{7} = \sqrt{14}$



$G) 2\sqrt{2} + \sqrt{2^{2} . 2^{2}} . \sqrt{2} + \sqrt{3^{2} . 2^{2}} . \sqrt{2} - 5 \sqrt{2} 2\sqrt{2} + 4\sqrt{2} + 6\sqrt{2} - 5\sqrt{2} 7 \sqrt{2}$

Answer 2

$\sqrt{112} = \sqrt{16.7} = 4 \sqrt{7}$

$\sqrt{28} = \sqrt{4.7} =2 \sqrt{7}$

E) $4 \sqrt{7} + \sqrt{14} - 2 \sqrt{7} = 2 \sqrt{7} + \sqrt{14}$

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 $\sqrt{8} = 2 \sqrt{2}$

$\sqrt{32} = 4 \sqrt{2}$

$\sqrt{72} = \sqrt{36.2 } = 6 \sqrt{2}$

$\sqrt{50} = \sqrt{2 . 25} = 5 \sqrt{2}$

G) $2 \sqrt{2} + 4 \sqrt{2} + 6 \sqrt{2} - 5 \sqrt{2} = 7 \sqrt{2}$