Question

determine o perímetro do triângulo LUZ, sabendo que LZ=50 e ZU=37,5​

Answer 1

$\large\boxed{\begin{array}{l}\sf 2p\longrightarrow per\acute imetro~do~\triangle\,LUZ.\\\sf 2p=\overline{LZ}+\overline{ZU}+\overline{LU}\\\sf 2p=50+37,5+40\\\sf 2p=127,5~u\cdot c\\\rm nota:\\\sf~a~sigla~u\cdot c~significa\,unidades\,de\,comprimento\end{array}}$