Question

No triângulo abaixo determine as medidas
dos segmentos CE e BE:​

Answer 1

$\frac{14}{10} =\frac{21}{y}\\\\\\14*y=21*10\\14y=210\\y=210/14\\y=15$

$\frac{4}{10} =\frac{x}{15} \\\\10*x=15*4\\10x=60\\x=60/10\\x=6$

resposta: y=15 e x=6