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respondido por:
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Resposta:
How do you find the limit of
5
x
2
−
8
x
−
13
x
2
−
5
as x approaches 3?
Calculus Determining Limits Algebraically
1 Answer
Jim H
Mar 6, 2015
Use the properties of limits.
lim
x
→
3
(
x
2
−
5
)
=
lim
x
→
3
x
2
−
lim
x
→
3
5
(Subtraction property)
=
(
lim
x
→
3
x
)
2
−
lim
x
→
3
5
(Power property)
=
3
2
−
5
(Limits of Identity and constant functions)
=
9
−
5
=
4
(Arithmetic)
Because the limit of the denominator is not
0
, we can use the quotient property for limits.
By steps similar to those above, we can show that
lim
x
→
3
(
5
x
2
−
8
x
−
13
)
=
5
(
3
)
2
−
8
(
3
)
−
13
=
45
−
37
=
8
.
And, therefore
lim
x
→
3
5
x
2
−
8
x
−
13
x
2
−
5
=
8
4
=
2
.
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