Question

Qual o valor do 11o termo da P.A ( 3, 6, 9, ..)

Answer 1

$\large\boxed{\begin{array}{l}\sf r=6-3=3\\\sf a_{11}=a_3+8r\\\sf a_{11}=9+8\cdot3\\\sf a_{11}=9+8\cdot3\\\sf a_{11}=9+24\\\sf a_{11}=33\end{array}}$