Question

$\lim_{n \to \infty} \frac{x^{2} -1}{x-1}$

Answer 1

$\lim_{x \to \infty} \frac{x^{2} -1}{x-1} = \lim_{x \to \infty} \frac{(x+1).(x-1)}{x-1}= \lim_{x \to \infty} {x+1} = \infty+1 =\infty$

Resposta: $\infty$