Question

4ª) calcular: a) (2x + y + 3) + (-5x + y – 1) = b) X² - 3x +5 + x² + 2x – 4) =
c) (3ab – 6a²) + (a² - 4ab + 2b²) + (5a² -3b²) =​

Answer 1

Resposta:

a) (2x + y + 3) + (-5x + y – 1)

$2x + y + 3 - 5x + y - 1 \\ - 3x + 2y + 2$

b) X² - 3x +5 + x² + 2x – 4

$2 {x}^{2} - x + 1$

c) (3ab – 6a²) + (a² - 4ab + 2b²) + (5a² -3b²)

$3ab - 6 {a}^{2} + {a}^{2} - 4ab + 2 {b}^{2} + 5 {a}^{2} - 3 {b}^{2} \\ - ab - {b}^{2} \\ - {b}^{2} - ab$