• Matéria: Matemática
  • Autor: rnovais605
  • Perguntado 3 anos atrás

Calcule corretamente: a) cos 30; b) cos 120; c) cos 210 e d) cos 300​

Respostas

respondido por: justforthebois123
1

Resposta:

a) \frac{\sqrt{3}}{2}

b) -\frac{1}{2}

c) -\frac{\sqrt{3}}{2}

d) \frac{1}{2}

Explicação passo a passo:

a) \cos \left(30^{\circ \:}\right)

=\frac{\sqrt{3}}{2}

b) \cos \left(120^{\circ \:}\right)

=\sin \left(90^{\circ \:}-120^{\circ \:}\right)

=\sin \left(-30^{\circ \:}\right)

=-\sin \left(30^{\circ \:}\right)

=-\frac{1}{2}

c) \cos \left(210^{\circ \:}\right)

=\cos \left(180^{\circ \:}+30^{\circ \:}\right)

=\cos \left(180^{\circ \:}\right)\cos \left(30^{\circ \:}\right)-\sin \left(180^{\circ \:}\right)\sin \left(30^{\circ \:}\right)

=\left(-1\right)\frac{\sqrt{3}}{2}-0\cdot \frac{1}{2}

=-\frac{\sqrt{3}}{2}

d) \cos \left(300^{\circ \:}\right)

=\sin \left(90^{\circ \:}-300^{\circ \:}\right)

=\sin \left(-210^{\circ \:}\right)

=-\sin \left(210^{\circ \:}\right)

=-\left(-\frac{1}{2}\right)

=\frac{1}{2}

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