Question

como resolver 3-[-1/2-(0,1+1/4)]=

Answer 1

$<var>3-[-\frac12-(0,1+\frac14)]=3-[-\frac12-(\frac1{10}+\frac14)]=\frac{60}{20}-[\frac{-10-2-5}{20}]=</var>$

 

$=\frac{60+17}{20}<var>=\frac{77}{20}=3,85</var>$

Answer 2

Observe que:

 

$0,1=\dfrac{1}{10}$

 

Seja $\text{X}=3-\left\lceil-\dfrac{1}{2}-\left(\dfrac{1}{10}+\dfrac{1}{4}\right)\right\rceil$

 

Desta maneira, temos que:

 

$\text{X}=3-\left\lceil-\dfrac{1}{2}-\dfrac{7}{20}\right\rceil$

 

Note que $\text{mmc}(2, 20) = 20$

 

$\text{X}=3+\dfrac{17}{20}$

 

Observe que $\text{mmc}(1, 20) = 20$.

 

Contudo, podemos afirmar que:

 

$\text{X}=\dfrac{60+17}{20}=\dfrac{77}{20}$