Question

2x-y-z=0
-2x-y+z=4
x+y-z=6, sistema linear.Por FAVOR PRESCISO URGENTE DA RESPOSTA.​

Answer 1

$\{2x-y-z=0\\\{-2x-y+z=4\\\{x+y-z=6$

$(-2x-y+z)+(x+y-z)=4+6\\-2x-y+z+x+y-z=10\\-x=10\\x=-10$

$(2x-y-z)+(-2x-y+z)=0+4\\2x-y-z-2x-y+z=4\\-2y=4\\2y=-4$

$y=-\frac{4}{2}$

$y=-2$

$x+y-z=6\\-10-2-z=6\\-z=6+10+2\\-z=18\\z=-18$