Question

Quantos termos tem a PG (8,32,...2³¹)?

Answer 1

Resposta:

PG

u1 = 2^3

u2 = 2^5

q = u2/u1 = 2^2

termo geral

un = u1*q^(n - 1)

2^31 = 2^3 * (2^2)^(n - 1)

4^(n - 1) = 2^28

2^(2n - 2) = 2^28

2n - 2 = 28

2n = 30

n = 15 temos