Question

Dada a função exponencial f(x) = 4^x, determine:

a) f (1/2)

b) f (-1/2)​

Answer 1

Resposta:

a= 2

b= $\frac{1}{2}$

Explicação passo a passo:

a)

$f(x) = 4^x\\f(\frac{1}{2}) = 4^{\frac{1}{2} } \\f(\frac{1}{2})= (2^2)^{\frac{1}{2} } \\f(\frac{1}{2})= 2^2.^{\frac{1}{2} } \\f(\frac{1}{2})= 2.^{\frac{1}{2 }=1$= 2.1/2 = 2/1.1/2 =1

$f(\frac{1}{2} ) = 2^1\\f(\frac{1}{2})= 2$

b)

$f(\frac{-1}{2}) = 4^{\frac{-1}{2} } \\f(\frac{-1}{2})= (2^2)^{\frac{-1}{2} }\\f(\frac{-1}{2})= 2^2.^{\frac{-1}{2} }\\f(\frac{-1}{2}) = 2.^{\frac{-1}{2} \\ = 2/1.-1/2= -1/1$=-1

$f(\frac{-1}{2}) = 2^{-1} \\f(\frac{-1}{2}) = \frac{1}{2}$