Question

ache o valor de delta
a) 3x²-6x+3=0
b)x²-4x+1=0
c)6x²+2x-4=0
d)x²-x+1=0​

Answer 1

Sua Pergunta

ache o valor de delta

a) 3x²-6x+3=0

a = 3 b= -6 c = 3

∆= b² - 4ac

∆= ( -6 )² - 4 . 3 . 3

∆= 36 - 36

∆= 0

b)x²-4x+1=0

a = 1 b = -4 c = 1

∆= b² - 4ac

∆= ( -4 )² - 4 . 1 . 1

∆= 16 - 4

∆= 12

c)6x²+2x-4=0

a = 6 b = 2 c = -4

∆= b² - 4ac

∆= 2² - 4 . 6 . ( -4 )

∆= 4 + 96

∆= 100

d)x²-x+1=0

a= 1 b= -1 c= 1

∆= b² - 4ac

∆= ( -1 )² - 4 . 1 . 1

∆= 1 - 4

∆= -3

espero ter ajudado!!