Question

sendo log 2= a, log 3= b e log 5= C, calcule

a) log 6

b) log 3/5

c) log 15

d) log 30

e) log 2/3​

Answer 1

Resposta:

Explicação passo a passo:

log 6=

log 2.3=

log 2 +log 3=

a+b

log 3/5=

log 3 -log 5=

b-c

log 15=

log 3.5=

log 3 +log 5=

b+c

log 30=

log 2.3.5=

log 2+ log 3+log 5=

a +b+c

log 2/3=

log 2-log 3=

a-b