Question

$\frac{1}{ \sqrt[]{2}}+\frac{1}{ \sqrt[]{18}} -\frac{1}{ \sqrt[]{8}}$

Answer 1

Resposta:

$\frac{11\sqrt{2} }{12}$

Explicação passo a passo:

$\frac{1}{\sqrt{2}}+\frac{1}{3\sqrt{2} }+\frac{1}{2\sqrt{2} }=\frac{6+2+3}{6\sqrt{2} } =\frac{11}{6\sqrt{2} }=\frac{11\sqrt{2} }{6.2}= \frac{11\sqrt{2} }{12}$