Question

02– Resolva as equações, sendo U = Q:


a) 3 – (3x – 6) = 2x + (4 – x)


b) 4(x – 2) = 4 + 2(x – 1)


c) 2(y – 2) + 5(2 – y) = - 3(2y + 2)


d) 7x – 3(x – 2) = 3(x + 4)

Answer 1

Resposta:

a) 3 – (3x – 6) = 2x + (4 – x)

$- 3x - 18 = 8x - 2 {x}^{2} \\ - 3x - 18 - 8x + 2 {x}^{2} = 0 \\ 2 {x}^{2} - 11x - 18 = 0$

b) 4(x – 2) = 4 + 2(x – 1)

$4x - 8 = 4 + 2x - 2 \\ 4x - 8 - 4 - 2x + 2 = 0 \\ 2x - 10 = 0 \\ 2x = 10 \div (2) \\ x = 5$

c) 2(y – 2) + 5(2 – y) = - 3(2y + 2)

$2y - 4 + 10 - 5y = - 6y - 6 \\ - 3y + 6 + 6y + 6 = 0 \\ 3y + 12 = 0 \\ 3y = - 12 \div (3) \\ y = - 4$

d) 7x – 3(x – 2) = 3(x + 4)

$7x - 3x + 6 = 3x + 12 \\ 4x + 6 - 3x - 12 = 0 \\ x - 6 = 0 \\ x = 6$