• Matéria: Matemática
  • Autor: alanakarolinemasquio
  • Perguntado 3 anos atrás

Determine a equação reduzida da reta que passa pelos pontos A (5, -2) e B(4,2).
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Respostas

respondido por: CyberKirito
0

\Large\boxed{\begin{array}{l}\underline{\rm Coeficiente~angular~da~reta}\\\underline{\rm que~passa~pelos~pontos}\\\underline{\rm A(x_A,y_A)~B(x_B,y_B)}\\\\\sf m=\dfrac{y_B-y_A}{x_B-x_A}\\\\\underline{\rm Equac_{\!\!,}\tilde ao~da~reta~passa~por~P(x_0,y_0)}\\\underline{\rm e~tem~coeficiente~angular~m}\\\sf y= y_0+m\cdot(x-x_0)\\\underline{\rm Equac_{\!\!,}\tilde ao~reduzida~da~reta}\\\sf y=mx+n\\\sf m\longrightarrow coeficiente~angular\\\sf n\longrightarrow coeficiente~linear\end{array}}

\Large\boxed{\begin{array}{l}\sf A(5,-2)~B(4,2)\\\sf c\acute alculo~do~coeficiente~angular:\\\sf m=\dfrac{2-[-2]}{4-5}=\dfrac{2+2}{-1}\\\\\sf m=\dfrac{4}{-1}=-4\\\sf adotando~o~ponto~B(4,2)~temos:\\\sf y=2-4\cdot(x-4)\\\sf y=2-4x+16\\\sf y=-4x+18\end{array}}

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