Question

AJUDA NESSA AQUI PFVR.... :3

Answer 1

$4^{3x}=16$
$4^{3x}=4^2$
$3x=2$
$x=\frac23$

$(\frac13)^x=81$
$(3^{-1})^x=3^4$
$3^{-x}=3^4$
$-x=4$
$x=-4$

$4x^2-2x=0$
$2x(2x-1)=0$
$2x=0$
$x=0$
$ou$
$2x-1=0$
$x=\frac12$

Essa ultima nao contem raiz pertencente aos reais.