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Boa noite Tatiane!
Para saber o valor de x basta lembrar de algumas relações trigonométricas básicas.
Exercício d
![tg(x)= \dfrac{Cateto~~oposto}{Cateto~~adjacente}\\\\\\\\\
tg(x)= \dfrac{5 \sqrt{3} }{5}\\\\\\
tg(x)= \sqrt{3}\\\\\
x= \sqrt{3}\\\\\
x=60\º](https://tex.z-dn.net/?f=tg%28x%29%3D++%5Cdfrac%7BCateto%7E%7Eoposto%7D%7BCateto%7E%7Eadjacente%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%0Atg%28x%29%3D+%5Cdfrac%7B5+%5Csqrt%7B3%7D+%7D%7B5%7D%5C%5C%5C%5C%5C%5C%0Atg%28x%29%3D+%5Csqrt%7B3%7D%5C%5C%5C%5C%5C%0Ax%3D+%5Csqrt%7B3%7D%5C%5C%5C%5C%5C%0Ax%3D60%5C%C2%BA+++ "tg(x)= \dfrac{Cateto~~oposto}{Cateto~~adjacente}\\\\\\\\\
tg(x)= \dfrac{5 \sqrt{3} }{5}\\\\\\
tg(x)= \sqrt{3}\\\\\
x= \sqrt{3}\\\\\
x=60\º")
Exercício e
Nesse exercício vamos aplicar o teorema de Pitágoras para acharmos o valor do cateto oposto.
![(12 \sqrt{3})^{2}=(18)^{2}+C^{2}\\\\\
144.3=324+C^{2}\\\\\
432=324+C^{2}\\\\\
432-324+C^{2}\\\\\
108=C^{2}\\\\
C= \sqrt{108}\\\\\
C=6 \sqrt{3}\\\\\\\\
tg(x)= \dfrac{6 \sqrt{3} }{18}\\\\\\\
tg(x)= \dfrac{ \sqrt{3} }{3}\\\\\\\
x= \dfrac{ \sqrt{3} }{3}\\\\\
x=30\º](https://tex.z-dn.net/?f=%2812+%5Csqrt%7B3%7D%29%5E%7B2%7D%3D%2818%29%5E%7B2%7D%2BC%5E%7B2%7D%5C%5C%5C%5C%5C%0A144.3%3D324%2BC%5E%7B2%7D%5C%5C%5C%5C%5C%0A432%3D324%2BC%5E%7B2%7D%5C%5C%5C%5C%5C%0A432-324%2BC%5E%7B2%7D%5C%5C%5C%5C%5C%0A108%3DC%5E%7B2%7D%5C%5C%5C%5C%0AC%3D+%5Csqrt%7B108%7D%5C%5C%5C%5C%5C%0AC%3D6+%5Csqrt%7B3%7D%5C%5C%5C%5C%5C%5C%5C%5C%0A+tg%28x%29%3D+%5Cdfrac%7B6+%5Csqrt%7B3%7D+%7D%7B18%7D%5C%5C%5C%5C%5C%5C%5C%0Atg%28x%29%3D+%5Cdfrac%7B+%5Csqrt%7B3%7D+%7D%7B3%7D%5C%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B++%5Csqrt%7B3%7D+%7D%7B3%7D%5C%5C%5C%5C%5C%0Ax%3D30%5C%C2%BA++++++++ "(12 \sqrt{3})^{2}=(18)^{2}+C^{2}\\\\\
144.3=324+C^{2}\\\\\
432=324+C^{2}\\\\\
432-324+C^{2}\\\\\
108=C^{2}\\\\
C= \sqrt{108}\\\\\
C=6 \sqrt{3}\\\\\\\\
tg(x)= \dfrac{6 \sqrt{3} }{18}\\\\\\\
tg(x)= \dfrac{ \sqrt{3} }{3}\\\\\\\
x= \dfrac{ \sqrt{3} }{3}\\\\\
x=30\º")
Boa noite!
Bons estudos!
Para saber o valor de x basta lembrar de algumas relações trigonométricas básicas.
Exercício d
Exercício e
Nesse exercício vamos aplicar o teorema de Pitágoras para acharmos o valor do cateto oposto.
Boa noite!
Bons estudos!
tatianealmeida02:
eu não entendi
O que você não entendeu?
esse negócios que tem tex e num sei oque e nun sei oque
Ta, então estuda mais que você aprende.
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