Question

1) calcule: x dy dx d =

2) arme a integral dupla em coordenadas polares da função

Answer 1

$\large\begin{array}{lr}\rm 01: \\ \displaystyle \rm \int_{0}^{1} \int_{0}^{1} \int_{0}^{1-x} x \, dydxdz = \frac{1}{6} \: u.m \\\\ \rm 02: \\ \displaystyle \rm \int_{0}^{\tfrac{\pi}{2}} \int_{1}^{2} R^2\, dRd\theta \end{array}$