Question

alguém pode me ajudar a resolver essas fórmulas de Bhaskara?até essa semana se conseguir,obrigado​

Answer 1

e) x² + 12x - 28 = 0

a = 1

b = 12

c = - 28

∆ = b² - 4 . a . c

∆ = 12² - 4 . 1 . (-28)

∆ = 144 + 112

∆ = 256

x = - b ± √∆

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2a

x' = - 12 - 16

------------

2 . 1

x' = - 28

-----

2

x' = - 14

x" = - 12 + 16

------------

2 . 1

x" = 4

---

2

x" = 2

S = {-14 , 2}

f) x² - 11x = - 10

x² - 11x + 10 = 0

a = 1

b = - 11

c = 10

∆ = b² - 4 . a. c

∆ = (-11)² - 4 . 1 . 10

∆ = 121 - 40

∆ = 81

x = - b ± √∆

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2a

x' = - (-11) - 9

-------------

2 . 1

x' = 11 - 9

------

2

x' = 2

---

2

x' = 1

x" = - (-11) + 9

-------------

2 . 1

x" = 11 + 9

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2

x" = 20

----

2

x" = 10

S = {1 , 10}

g) 6x² - 5x + 1 = 0

a = 6

b = - 5

c = 1

∆ = b² - 4 . a . c

∆ = (-5)² - 4 . 6 . 1

∆ = 25 - 24

∆ = 1

x = - b ± √∆

-------------

2a

x' = - (-5) - 1

------------

2 . 6

x' = 5 - 1

------

12

x' = 4 (÷4)

---

12 (÷4)

x' = 1

---

3

x" = - (-5) + 1

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2 . 6

x" = 5 + 1

-------

12

x" = 6 (÷6)

---

12 (÷6)

x" = 1

---

2

S = {1/3 , 1/2}

h) -3y² + 1 = -2y

-3y² + 2y + 1 = 0

a = - 3

b = 2

c = 1

∆ = b² - 4 . a . c

∆ = 2² - 4 . (-3) . 1

∆ = 4 + 12

∆ = 16

y = - b ± √∆

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2a

y' = - 2 - 4

----------

2 . (-3)

y' = - 6

-----

- 6

y' = 1

y" = - 2 + 4

----------

2 . (-3)

y" = 2 (÷2)

----

- 6 (÷2)

y" = - 1

---

3

S = {1 , -1/3}

i) m + 4 = m² - 3m + 7

-m² + 3m + m + 4 - 7

-m² + 4m - 3 = 0

a = - 1

b = 4

c = - 3

∆ = b² - 4 . a . c

∆ = 4² - 4 . (-1) . (-3)

∆ = 16 - 12

∆ = 4

m = - b ± √∆

------------

2a

m' = - 4 - 2

---------

2 . (-1)

m' = - 6

----

- 2

m' = 3

m" = - 4 + 2

----------

2 . (-1)

m" = - 2

-----

- 2

m" = 1

S = {3 , 1}