• Matéria: Matemática
  • Autor: lisaasouza71
  • Perguntado 3 anos atrás

respostas certas por favor obrigada​

Anexos:

Respostas

respondido por: JohanLiebert
2

Resposta:

Resposta da Matriz A:

\left[\begin{array}{ccc}0&12&20\\-1&13&22\\-2&14&24\end{array}\right]\left\begin{array}{ccc}0&12\\-1&13\\-2&14\end{array}\right|\\\\\\Multiplicando\ crusado\ vamos\ obter:\\\\=0\bullet13\bullet24+12\bullet22\bullet-2+20\bullet-1\bullet14-(12\bullet-1\bullet24)-(0\bullet22\bullet14)-(20\bullet13\bullet-2)\\\\=0-528-280+288-0+520\\\\=-808+808=0\\\\detA=0

Resposta da Matriz B:

\left[\begin{array}{ccc}0&10\\7&17\end{array}\right]\\\\\\Multiplicando cruzado vamos obter:\\\\=0\bullet17-(10\bullet7)\\\\=0-70=-70\\\\detB=-70

Resposta da Matriz C:

\left[\begin{array}{ccc}23\end{array}\right]\\\\detC=23

Resposta da Matriz D:

\left(\begin{array}{ccc}12&14\\11&13\end{array}\right)\\\\\\Multiplicando\ cruzado\ vamos\ obter:\\\\=12\bullet13-(14\bullet11)\\\\=156-154=2\\\\detD=2

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