Question

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Calcule o valor numérico da expressão:

Answer 1

$\large\boxed{\begin{array}{l}\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}~~para\,a=2,b=-10~e~c=12\\\\\sf x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\cdot2\cdot12}}{2\cdot2}\\\\\sf x=\dfrac{10\pm\sqrt{100-96}}{4}\\\\\sf x=\dfrac{10\pm\sqrt{4}}{4}\\\\\sf x=\dfrac{10\pm2}{4}\\\rm aqui\,temos\,dois\,poss\acute iveis\,valores\,para\,x.\\\sf x_1=\dfrac{10+2}{4}=\dfrac{12}{4}=3\\\\\sf x_2=\dfrac{10-2}{4}=\dfrac{8}{4}=2\end{array}}$

Answer 2

Explicação passo-a-passo:

$x = \dfrac{ - b \dfrac{ + }{} \sqrt{b {}^{2} - 4ac} }{2a}$

$para$

$a = 2$

$b = - 10$

$c = 12$

___________________________

$x = \dfrac{10 \dfrac{ + }{} \sqrt{( - 10) {}^{2} - 4 \times 2 \times 12 } }{2 \times 2}$

$x = \dfrac{10 \dfrac{ + }{} \sqrt{100 - 96} }{4}$

$x = \dfrac{10 \dfrac{ + }{} \sqrt{4} }{4}$

$x = \dfrac{10 \dfrac{ + }{} 2}{4}$

x¹=10+2/4=12/4=>3

x²=10-2/4=8/4=>2