Question

Duvida na seguinte:
log[3-2log(x+1)]=0

Answer 1

$log[3-2log(x+1)]=0 \\ \\ log[3-2log(x+1)]=log10^0 \\ \\ 3-2log(x+1)=10^0 \\ \\ 3-2log(x+1)=1 \\ \\ -2log(x+1)=1-3 \\ \\ -2log(x+1)=-2 \\ \\ 2log(x+1)=2 \\ \\ log(x+1)=1 \\ \\ log(x+1)=log10^1 \\ \\ x+1=10^1 \\ \\ x+1=10 \\ \\ x=9$