Question

Quais são as raízes da equação x² - 74x +1200 = 0

Answer 1

Resposta: 50;24

Explicação passo a passo:

$x =\frac{\ -b +/-\sqrt{b2-4.a.c} \\}{2.a} \\\\ x =\frac{\ -(74) +/-\sqrt{(-74)^2-4.1.1200} \\}{2.1} \\\\x1= \frac{\ +74 +\sqrt{5476-4800} \\}{2} \\\\\\\\\sqrt{676} = 26\\\\x1= \frac{74+26}{2} \\=50\\x2= \frac{74-26}{2} =24$