Question

x2 -18x +45=0 ajuda ae por favor

Answer 1

$x^{2}-18x+45=0$
$x=\frac{-b\pm\sqrt{\Delta}}{2a}$
$x=\frac{-(-18)\pm\sqrt{\Delta}}{2*1}$
$x=\frac{18\pm\sqrt{\Delta}}{2}$
$\Delta=b^{2}-4ac$
$\Delta=(-18)^{2}-4*1*45$
$\Delta=324-180$
$\Delta=144$
$x=\frac{18\pm\sqrt{144}}{2}$
$x=\frac{18\pm12}{2}$
$x=9\pm6$
$x_{1}=9+6$
$x_{1}=15$
$x_{2}=9-6$
$x_{2}=3$

Answer 2

$x^{2} -18x+45$
Fórmula de Delta
Δ= b²-4×a×c
Δ=(-18)²-4×1×45
Δ= 324 - 180
Δ = 144

Fórmula de Bhaskara

$x = \frac{18 \frac{+}{} \sqrt{Delta} }{2*a}$

$x= \frac{-(-18) \frac{+}{} \sqrt{144} }{2*1}$

$x= \frac{18 \frac{+}{} 12 }{2}$

$x1= \frac{18+12 }{2}= \frac{30}{2} = 15$

$x2= \frac{18 - 12 }{2}= \frac{6}{2} = 3$

S = { 15, 3 }