Question

Racionalize PF AJUDEM!!!!!!!!!!

3-√3
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3√3-3

Answer 1

$\frac{3- \sqrt{3} }{3 \sqrt{3-3} } = \frac{3- \sqrt{3} }{ \sqrt{27-3} } * \frac{ \sqrt{27+3} }{ \sqrt{27+3} } = \frac{3 \sqrt{27}+9- \sqrt{81}-3 \sqrt{3} }{( \sqrt{27)^2}-3^2 } =$

$\frac{9 \sqrt{3}+9-9 - 3 \sqrt{3} }{27 - 9} = \frac{6 \sqrt{3} }{18} = \frac{ \sqrt{3} }{3}$