Question

. alguém me ajuda pfvr ​

Answer 1

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A)

Log¹⁰(26) =>

Log¹⁰(2) + Log¹⁰(13) =>

0,3010 + 1,1139 =>

=> 1,4149

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B)

Log¹⁰(13/2) =>

Log¹⁰(13) - Log¹⁰(2) =>

1,1139 - 0,3010 =>

=> 0,8129

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C)

Log¹⁰(169) =>

2log¹⁰(13) =>

2(1,1139) =>

=> 2,2278

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Att: MarcosPCV