Question

Determine x na expressão log x=
$\frac{1}{3}$ [2.log a+ $\frac{1}{3}$ log b+3.colog c-2.colog d

Answer 1

log x = [2.log a + (1/3).log b + 3.colog c - 2.colog d]/3

3.log x = log a^2 + log b^(1/3) - log c^3 + log d^2

3.log x = log a^2 + log b^(1/3) + log c^(-3) + log d^2

log x^3 = log [a^2.b^(1/3).c^(-3).d^2]

x^3 = a^2.b^(1/3).c^(-3).d^2

x = [a^2.b^(1/3).c^(-3).d^2]^(1/3)

x = a^(2/3).b^(1/9).c^(-3/3).d^(2/3)

x = a^(2/3).b^(1/9).c^(-1).d^(2/3).

Answer 2

Resposta:

olá, o amigo ai em cima respondeu certo?