Question

calcule os valores dos logaritmos a seguir, considerando log2= 0,301 e log3= 0,477
a) log36
b) log72
c) log2187
d) log3
e) log 1,5
f) log 2/3

Answer 1

a) log36
log(3^2.2^2)
log(3^2) + log(2^2)
2.log3 + 2.log2
2.(log3+log2)
2.(0,301+0,477)
2.(0,778)
2.(778/1000)
1556/1000
1,556

b) log72
log(3^4.2^4)
log(3^4) + log(2^4)
4.log(3) + 4.log(2)
4.(log3 + log2)
4.(0,778)
4.(778/1000)
3112/1000
3,112

c) log2187
*fatorando
2187 | 3
729 | 3
243 | 3
81 | 3
27 | 3
9 | 3
3 | 3
1
3^7
log(3^7)
7.log(3)
7.0,477
7.477/1000
3339/1000
3,339

d) 0,477

e) log 1,5
log (3/2)
log3 - log2
0,477 - 0,301
0,176

f) log2/3
log 2 - log 3
0,301 - 0,477
-0,176