Question

podem me ajuda nessa questão? é sobre função logarítmica​

Answer 1

Resposta:

Explicação passo a passo:

Mano consegui resolver e a resposta deu 49/54

Answer 2

Resposta:

$\frac{49}{54}$

Explicação passo a passo:

$\frac{log_{\frac{1}{27}}\sqrt[3]{243}-3.log_{0,01}10000}{log_{\sqrt{3}}27}\\\\\frac{log_{\frac{1}{27}}\sqrt[3]{243}-3.log_{0,01}10000}{log_{3^{\frac{1}{2}}}27}\\\\\frac{log_{\frac{1}{27}}\sqrt[3]{243}-3.log_{0,01}10000}{2.log_{3}27}\\\\\frac{log_{\frac{1}{27}}\sqrt[3]{243}-3.log_{0,01}10000}{2.3}\\\\\frac{log_{\frac{1}{27}}\sqrt[3]{243}-3.log_{0,01}10000}{6}\\\\\frac{log_{\frac{1}{27}}\sqrt[3]{243}-3.log_{10^{-2}}10^4}{6}$

$\frac{log_{\frac{1}{27}}\sqrt[3]{243}-(\frac{-3.4}{-2})log_{10}10}{6}\\\\\frac{log_{\frac{1}{27}}\sqrt[3]{243}+6.log_{10}10}{6}\\\\\frac{log_{\frac{1}{27}}\sqrt[3]{243}+6.1}{6}$

$\frac{\frac{1}{-3}.log_3\sqrt[3]{3^5}+6}{6} \\ \\\frac{\frac{1}{-3}.log_33^{\frac{5}{3}}+6}{6}\\\\\frac{\frac{1}{-3}.\frac{5}{3}.log_33+6}{6}\\\\\frac{-\frac{5}{9}.1+6}{6}\\\\\frac{-\frac{5}{9}+\frac{54}{9} }{6}\\\\\frac{\frac{49}{9}}{6}\\\\\frac{49}{54}$