• Matéria: Matemática
  • Autor: nancypereira9042
  • Perguntado 3 anos atrás

Dertemine a medida do elemento desconhecido nos triângulos retângulos

Anexos:

Respostas

respondido por: CyberKirito
0

\large\boxed{\begin{array}{l}\sf a)~\rm a^2=3^2+4^2\\\rm a^2=9+16\\\rm a^2=25\\\rm a=\sqrt{25}\\\rm a=5\\\sf b)~\rm b^2+8^2=10^2\\\rm b^2+64=100\\\rm b^2=100-64\\\rm b^2=36\\\rm b=\sqrt{36}\\\rm b=6\\\sf c)~\rm a^2=5^2+12^2\\\rm a^2=25+144\\\rm a^2=169\\\rm a=\sqrt{169}\\\rm a=13\\\sf d)~\rm c^2+12^2=15^2\\\rm c^2+144=225\\\rm c^2=225-144\\\rm c^2=81\\\rm c=\sqrt{81}\\\rm c=9\end{array}}

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