Question

Alguem pode mim ajuda 6x²+19x-7=0

Answer 1

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$6 {x}^{2} + 19x - 7 = 0$

${6x}^{2} + 21x - 2x - 7 = 0$

$3x \times (2x + 7) - 2x - 7 = 0$

$3x \times (2x + 7) - (2x + 7) = 0$

$(2x + 7) \times (3x - 1) = 0$

$2x + 7 = 0 \\ 3x - 1 = 0$

$2x = - 7 \\ 3x - 1 = 0$

$x = - \frac{7}{2} \\ 3x - 1 = 0$

$x = - \frac{7}{2} \\ 3x = 1$

$x = - \frac{7}{2} \\ x = \frac{1}{3}$

$\boxed{ \color{green} \boxed{{ x _{1} = - \frac{7}{2} }}}\boxed{ \color{green} \boxed{{  x_{2} = \frac{1}{3} }}}$

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${\boxed{ \color{blue} \boxed{ 26 |02|22  }}}{\boxed{ \color{blue} \boxed{Espero \:  ter  \: ajudado \: ☆}}}$