Question

A solução da equação (0,1)^x = 20 é: (considere log2 = 0,3)

Answer 1

$\boxed{\begin{array}{l}\sf(0,1)^x=20\\\sf(10^{-1})^x=20\\\sf x=\log_{10^{-1}}20\\\sf x=-\log20\\\sf x=-[\log(2\cdot10)]\\\sf x=-[\log2+\log10]\\\sf x=-[0,3+1]\\\sf x=-[1,3]\\\sf x=-1,3\blue{\checkmark}\end{array}}$