Question

X^2 =4(x+8) me ajuda aí

Answer 1

x²=4x+32
x²-4x+32=0

Δ=(-4)²-4·1·32
Δ=16+128
Δ=144

x1 = ( -(-4) + √144 )/ 2·1
x1=(4+12)/2
x1=16/2
x1=8

x2 = ( -(-4) - √144 )/ 2·1
x2=(4-12)/2
x2=(-8)/2
x2=(-4)

S={8,(-4)}