Question

6). Calcule a soma dos termos da P.G. (12, 6, 3,...).

Answer 1

$> resolucao \\ \\ \geqslant progressao \: geometrica \\ \\ \\ \geqslant soma \: dos \: infinitos \: termos \: da \: pg(12 \: . \: 6 \: . \: 3.....) \\ \\ \\ q = \frac{a2}{a1} \\ \\ q = \frac{6}{12} \\ \\ q = \frac{1}{2} \\ \\ \\ \\ sn = \frac{a1}{q - 1} \\ \\ sn = \frac{12}{1 - \frac{1}{2} } \\ \\ sn = \frac{12}{ \frac{1}{2} } \\ \\ sn = 12 \times \frac{2}{1} \\ \\ sn = \frac{24}{1} \\ \\ sn = 24 \\ \\ \\ > < > < > < > < > < > < > < > < > <$