Question

Caucule o 9° termo da P.G.: (3,6,12,...)

Answer 1

a9= 768

$q = \frac{6}{3} \\ q = 2$

$an = a1 \times {q}^{n - 1} \\ a9 = 3 \times {}2^{8} \\ a9 = 3 \times 256 \\ a9 = 768$

Espero ter ajudado!

Answer 2

$> resolucao \\ \\ \geqslant progressao \: geometrica \\ \\ q = \frac{a2}{a1} \\ \\ q = \frac{6}{3} \\ \\ q = 2 \\ \\ \\ \geqslant o \: nono \: termo \: da \: pg \: \\ \\ \\ an = a1 \times q {}^{n - 1} \\ an = 3 \: \times \: 2 {}^{9 - 1} \\ an = 3 \: \times \: 2 {}^{8} \\ an = 3 \: \times \: 256 \\ an = 768 \\ \\ \\ \\ > < > < > < > < > < > < > < >$