Quantos que e:
a) (-8)-(+12)
b)(+15)-(-15)
c)(-50)-(+40)
d)(+117)-(+17)
e)(-86)-(-26)
f)(+100)-(+100)
Respostas
respondido por:
6
boa noite
a) (-8)-(+12)=
-8-12=
-20
b)(+15)-(-15)=
15+15=
30
c)(-50)-(+40)=
-50-40=
-90
d)(+117)-(+17)=
117-17=
100
e)(-86)-(-26)=
-86+26=
-60
f)(+100)-(+100)
100-100=
0
a) (-8)-(+12)=
-8-12=
-20
b)(+15)-(-15)=
15+15=
30
c)(-50)-(+40)=
-50-40=
-90
d)(+117)-(+17)=
117-17=
100
e)(-86)-(-26)=
-86+26=
-60
f)(+100)-(+100)
100-100=
0
respondido por:
1
Olá,
Vamos lá,
a) (-8)-(+12) =-8 - 12= - 20
b)(+15)-(-15) = 15 + 15 = 30
c)(-50)-(+40) = -50 - 40 = -90
d)(+117)-(+17) = 117 - 17 = 100
e)(-86)-(-26) = -86 + 26 = -60
f)(+100)-(+100) = 100 - 100 = 0
Vamos lá,
a) (-8)-(+12) =-8 - 12= - 20
b)(+15)-(-15) = 15 + 15 = 30
c)(-50)-(+40) = -50 - 40 = -90
d)(+117)-(+17) = 117 - 17 = 100
e)(-86)-(-26) = -86 + 26 = -60
f)(+100)-(+100) = 100 - 100 = 0
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