Question

$3x-4x+2=0$ Alguém me ajuda nessa fórmula de Bhaskara

Answer 1

Resposta:

$3x^2-4x+2=0$

Bhaskara:

$x_{1,\:2}=\frac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:3\cdot \:2}}{2\cdot \:3}$

$x_{1,\:2}=\frac{-\left(-4\right)\pm \:2\sqrt{2}i}{2\cdot \:3}$

$x_1=\frac{-\left(-4\right)+2\sqrt{2}i}{2\cdot \:3},\:x_2=\frac{-\left(-4\right)-2\sqrt{2}i}{2\cdot \:3}$

$x=\frac{2}{3}+i\frac{\sqrt{2}}{3},\:x=\frac{2}{3}-i\frac{\sqrt{2}}{3}$