• Matéria: ENEM
  • Autor: dasgamer77
  • Perguntado 3 anos atrás

126+√49 -{ 28-√16×[3×(40+5-3)+(17-3×4)]}

Respostas

respondido por: simonesantosaraujo91
2

Resposta:

504X^2+12x+88

Explicação:

126+V49-(28-V16×(3×(40+5-3)+(17-3×4))

126+V49-(28-V16x)3x(40+5-3)+(17-3x4))

126+V49-(28-V16x×(3x×(40+5-3)+(17-3x×4))

V49

V7^2

7

126+V49-(28-V16x×(3x×(40+5-3)+(17-3x×4))

126+7-(28-V16x×3x×+(40+5-3)+(17-3x×4))

126+V49-(28-V16x×(3x×+(40+5-3)+(17-3x×4))

V16

V4^2

4

126+V49-(28-V16x×(3x×(40+5-3)+(17-3x×4))

126+7-(28-4x×(3x×(40+5-3)+(17-3x×4))

126+V49-(28-V16(3x×(40+5-3)+(17-3x×4))

126+7-3(28-4x×3x×(40+5-3)+(17-3x×4))

126+V49-(28-V16x×(3x×(40+5-3)+(17-3x×4))

40+5-3

45-3

42

126+V49-(28-V16x×(3x×(40+5-3)+(17-3x×4))

126+7-(28-4x×3x×42+(17-3x×4))

126+V49-(28-V16x×(3x×(40+5-3)+(17-3x×4))

-3x×4

-(3×4)x

-12x

126+V49-(28-V16x×(3x×(40+5-3)+(17-3x×4))

126+7-(28-4x×3x×42+(17-12x))

-4x×3x×42

-504x×x

-4x×3x×42

-504x^2

126+7-(28-4x×3x×42+(17-12x))

126+7-(28-504x^2+(17-12x))

126+7-(28-4x×3x×42+(17-12x))

126+7-(28-504x^2+17-12x)

126+7-(45-504x^2-12x)

126+7-45+504x^2-12x

126+7-45

133-45

88

126+7-45+504x^2+12x

88+504x^2+12x

504x^2+12x+88

Resposta

504x^2+12x+88

respondido por: valdirnp72
1
Espero tê-lo (a)ajudado… bom dia 0405
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