Question

Calcule a soma dos numeros pares entre 2 e 100 usando a formula do pa

Answer 1

$> resolucao \\ \\ \geqslant progressao \: aritmetica \\ \\ an = a1 + (n - 1)r \\ 98 = 4 + (n - 1)2 \\ 98 = 4 + 2n - 2 \\ 98 = 2 + 2n \\ 98 - 2 = 2n \\ 96 = 2n \\ n = \frac{96}{2} \\ n = 48 \\ \\ = = = = = = = = = = = = = = = = = \\ \\ > soma \: dos \: termos \: da \: pa \\ \\ sn = \frac{(a1 + an)n}{2} \\ \\ sn = \frac{(4 + 98)48}{2} \\ \\ sn = \frac{102 \times 48}{2} \\ \\ sn = 102 \times 24 \\ \\ sn = 2448 \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant \geqslant$