Question

X²-X=7 usando bhaskara

Answer 1

Resposta:

$x^{2} -x=7\\ \\ x^{2} -x-7=0\\ \\ coeficientes:\\ a=1\\ b=-1\\ c=-7\\ \\ delta=b^{2} -4.a.c\\ \\ delta=(-1)^{2} -4.1.(-7)\\ \\ delta=1-(-28)\\ \\ delta=1+28\\ \\ delta=29\\ \\ x=\frac{-b+-\sqrt{delta} }{2.a} \\ \\ x=\frac{-(-1)+-\sqrt{29} }{2.1} \\ \\ x=\frac{1+-\sqrt{29} }{2} \\ \\ x'=\frac{1+\sqrt{29} }{2} \\ \\ x''=\frac{1-\sqrt{29} }{2} \\ \\ \\ S:\left \{ {{(\frac{1+\sqrt{29} }{2} )}, {(\frac{1-\sqrt{29} }{2} )}} \}$