Question

2= Calcule as equações :

x²+5x+6=0


x²-18x+45=0

Answer 1

Resposta:

x^2+5x+6=0

a=1 b=5 c=6

∆= b^2-4ac

∆= 5^2-4.1.6

∆= 1

X= -b+-√∆÷2a

X= -5+-√1÷2.1

X= -5+-1÷2

X'= -5-1= -6÷2=-3

X"= -5+1= -4÷2=-2

S= {-3,-2}

x^2-18x+45=0

a=1 b=-18 c=45

∆=b^2-4ac

∆=(-18)^2-4.1.45

∆=144

X= -b+-√∆÷2a

X= -18+-√144÷2.1

X= -18+-12÷2

X'= -18-12= -30÷2= -15

X"= -18+12= -6÷2= -3

S{-15,-3}

Espero Ter Ajudado! :3