• Matéria: Matemática
  • Autor: ronilces79
  • Perguntado 3 anos atrás

Poderia verificar o resultado das operações a seguir na forma de fração:
a) 0,37 + 2,011111...
b) 32,252525... + 8,02
c) 16,29797... – 0,002

Respostas

respondido por: baebergamota
0

Resposta:

Explicação passo a passo:

a.

2,01111...

x=2,0111...

10x=20,111...

100x=201,111...

100x-10x=201,111...-20,1111...

90x=181

x=181/90

0,37=37/100

0,37+2,01111....

37/100 + 181/90=

333/900+1810/900=

2143/900

b.

32,252525...

x=32,252525..

100x=3225,252525...

100x-x=3225,252525...-32,252525....

99x=3193

x=3193/99

8,02=802/100

32,252525...+8,02=

3193/99 + 802/100=

319300/9900+ 79398/9900=

398698/9900

c.

16,2979797... - 0,002=

16,2979797..

x=16,2979797...

10x=162,979797..

1000x=16297,979797...

1000x-10x=16297,979797...162,979797...

990x=16135

x=16135/990

0,002=2/1000

16,297979797.... -0,002=

16135/990 -2/1000=

1613500/99000-198/99000=

1613302/99000

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